6x^2+72x-252=0

Solution for 6x^2+72x-252=0 equation:

6x^2+72x-252=0

a = 6; b = 72; c = -252;
Δ = b2-4ac
Δ = 722-4·6·(-252)
Δ = 11232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11232}=\sqrt{144*78}=\sqrt{144}*\sqrt{78}=12\sqrt{78}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-12\sqrt{78}}{2*6}=\frac{-72-12\sqrt{78}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+12\sqrt{78}}{2*6}=\frac{-72+12\sqrt{78}}{12}
$